1A
B
C
D
E
F
G
H
I
J
2
3
Amount of wet material (m
wm
)
9933.7
lb/h
2.204622622
4
Moisture content (X
wm
)
62
%
5
Dry matter content (D
m
c)
38
%
6
Temperature of wet material (T
wm
)
176
o
F
7
Amount of dried material (m
dm
)
4289.55227
lb/h
2.204622622
8
Moisture content of dried material (X
d
)
12
%
9
Temperature of dried material (T
dm
)
176
o
F
10
Leak air (L
A
)
5
%
11
Temperature of hot inlet air (T
in
)
842
o
F
12
Temperature of outlet air (T
out
)
230
o
F
13
Temperature of ambient air (T
a
)
68
o
F
14
Net caloric value of fuel oil (NCVF)
17712.8117
Btu/lb
0.429922614
15
Entalphy of ambient air (h
3
a)
8.6427
Btu/lb
0.429922614
16
Entalphy of outlet air (h
2
a)
47.418
Btu/lb
0.429922614
17
Entalphy of inlet air (h
1
a)
199.4388
Btu/lb
0.429922614
18
Entalphy of water on Twm (h
1
w)
144.287
Btu/lb
0.429922614
19
Entalphy of water on Tout (h
2
w)
1158.007
Btu/lb
0.429922614
20
Entalphy of water vapor on Tin (h
3
w)
1452.3178
Btu/lb
0.429922614
21
Specific heat of nitrogen (cpN
2
)
0.26559664
Btu/lb
o
F
0.238845897
22
Specific heat of CO
2
(cpCO
2
)
0.28351008
Btu/lb
o
F
0.238845897
23
Specific heat of wet material (cpM
wet
)
0.55990255
Btu/lb
o
F
0.238845897
24
Specific heat of dry material (cp
dm
)
0.31981466
Btu/lb
o
F
0.238845897
25
Specific heat of dried material (cpM
dr
)
0.39003535
Btu/lb
o
F
0.238845897
26
Heat of evaporation of water (rH
2
O)
1074.805
Btu/lb
0.429922614
27
Specific heat of fuel on 60 °C (cp
f
)
0.52522213
Btu/lb
o
F
0.238845897
28
Temperature of fuel (T
f
)
140
o
F
29
30
Calculation of heat and mass balance:
31
Amount of dried material
m
dm
= m
wm
· ( 100-X
wm
) / 100 - X
d
m
dm
=
4289.552273
lb
32
33
Amount of water evapored
m
ev
= m
dm
· (X
wm
-X
d
) / 100-X
wm
m
ev
=
5644.147727
lb
34
35
lb/h
ft
3
/h
36
Required amount of hot (inlet) air
m
ha
= m
ev
· rH
2
O / (h
1
a - h
2
a)
m
ha
=
39904.79065
538770.54
37
38
Heat for water evaporation
Q
1
= m
ha
· h
1
a
Q
1
=
7958563.561
Btu/h
39
40
Outlet air heat content
Q
2
= m
ha
· (h
2
a - h
3
a)
Q
2
=
1547320.229
Btu/h
41
42
Total amount of heat
Q
U
= Q
1
+ Q
2
Q
U
=
9505883.79
Btu/h
43
44
lb/h
l/h
45
Required amount of fuel
m
f
= Qu / NCVF
m
f
=
536.6671286
570.92
46
47
Evaporation eficiency
C
ev
= m
ev
/ m
f
C
ev
=
10.5170364
lb H
2
O/lb fuel
48
CALCULATION DATA
